National Top Stream
Chapter 61 Proof
[Every even number greater than 4 must be the sum of two odd prime numbers. This is the famous Goldbach problem
Let 0=2, 1=3, 2=5, ..., 10=31, ..., n means that the nth odd prime number from small to large is set to an even number
……
If k|, that is, x≡0≡(odk) in this case, because the multiples of k and the congruent numbers modulo k and congruent numbers are of the same type, it is only necessary to remove the congruent number x of modulo k
That is, x≡0(odk), ,0
After removing the multiples of 1, 21, ..., n and the modulo 2, ..., n and the congruent number from the natural numbers from 1 to 1...n, the number of remaining numbers is: (1-d1)...(n-dn )k| when dk=1, k when dk=2, where k=1, 2,..., n removes the multiples and modulo 1 of 21, 2, 1,..., n from the natural numbers from 2 to 1...n, After 2, ..., n and the congruent number, the remaining numbers are not all prime numbers
……1】
【…
a0(odk), a(odk)(k=0, 1, 2, ..., n) and 1
……
If a is a number of h, b must be an odd prime number that is not a multiple of k, then b0(odk) is affirmative. If there is any i such that b≡(odi), (i=1, 2,..., one of n) Then a=-b is a multiple of i, which is contradictory to the h number that a is, so it can only be b(odk), so b is also a h number
In the sum of two odd prime numbers, except for kj, the addends in the sum of other two odd prime numbers are all h numbers
In fact, the h numbers obtained from natural numbers not greater than sieve are the same no matter whether they are sieved along or backwards. The calculated value is very close to the number of actual h numbers. For easy calculation, the inverted sieve calculation method is used
……2】
No one spoke in the entire academic lecture hall, not even a whispered discussion.
Everyone looked at the blackboard very seriously and intently, for fear of missing something, Zhuang Weiran is really too strong.
Many things that they hadn't figured out before, through the formula written by Zhuang Weiran on the blackboard, actually made them think through a lot.Faltins, who was sitting in the first row, whispered, "Interesting, the inverted sieve calculation method."
"It's really interesting." Witten also echoed, "In number theory, he can even be said to be one of the most powerful number theory masters in the world."
"No one would think that he only knows partial differential equations, right?"
"To be honest, as long as you have read his papers, you will know that his research is not far behind whether it is partial differential equations, algebra, or geometry. Even in the field of functional analysis, he is not far behind. Otherwise, his field theory would definitely not be possible.”
Zhuang Weiran is still writing on the blackboard, he has almost written three blackboards.The original one-hour academic report meeting has already passed half an hour, and everyone has not sensed the time. Why did half an hour pass in a blink of an eye?There is still half an hour left, can Zhuang Weiran solve the weak Goldbach conjecture?
In other words, has Zhuang Weiran really solved the weak Goldbach conjecture?This question came to everyone's mind, and they were looking forward to Zhuang Weiran's weak Goldbach's conjecture.
Zhuang Weiran's speed was getting faster and faster, and everyone felt dazzled.
Come to open the blackboard, Zhuang Weiran continued to write down the formula.
In 15 minutes, this academic report will be finished.Basically, everyone has already done a good job in the psychological construction of extending the academic report, and the weak Goldbach's conjecture cannot be written in an hour.Naturally, they didn't have any complaints. There are too many bosses at the scene, no matter what
Let 0=2, 1=3, 2=5, ..., 10=31, ..., n means that the nth odd prime number from small to large is set to an even number
……
If k|, that is, x≡0≡(odk) in this case, because the multiples of k and the congruent numbers modulo k and congruent numbers are of the same type, it is only necessary to remove the congruent number x of modulo k
That is, x≡0(odk), ,0
After removing the multiples of 1, 21, ..., n and the modulo 2, ..., n and the congruent number from the natural numbers from 1 to 1...n, the number of remaining numbers is: (1-d1)...(n-dn )k| when dk=1, k when dk=2, where k=1, 2,..., n removes the multiples and modulo 1 of 21, 2, 1,..., n from the natural numbers from 2 to 1...n, After 2, ..., n and the congruent number, the remaining numbers are not all prime numbers
……1】
【…
a0(odk), a(odk)(k=0, 1, 2, ..., n) and 1
……
If a is a number of h, b must be an odd prime number that is not a multiple of k, then b0(odk) is affirmative. If there is any i such that b≡(odi), (i=1, 2,..., one of n) Then a=-b is a multiple of i, which is contradictory to the h number that a is, so it can only be b(odk), so b is also a h number
In the sum of two odd prime numbers, except for kj, the addends in the sum of other two odd prime numbers are all h numbers
In fact, the h numbers obtained from natural numbers not greater than sieve are the same no matter whether they are sieved along or backwards. The calculated value is very close to the number of actual h numbers. For easy calculation, the inverted sieve calculation method is used
……2】
No one spoke in the entire academic lecture hall, not even a whispered discussion.
Everyone looked at the blackboard very seriously and intently, for fear of missing something, Zhuang Weiran is really too strong.
Many things that they hadn't figured out before, through the formula written by Zhuang Weiran on the blackboard, actually made them think through a lot.Faltins, who was sitting in the first row, whispered, "Interesting, the inverted sieve calculation method."
"It's really interesting." Witten also echoed, "In number theory, he can even be said to be one of the most powerful number theory masters in the world."
"No one would think that he only knows partial differential equations, right?"
"To be honest, as long as you have read his papers, you will know that his research is not far behind whether it is partial differential equations, algebra, or geometry. Even in the field of functional analysis, he is not far behind. Otherwise, his field theory would definitely not be possible.”
Zhuang Weiran is still writing on the blackboard, he has almost written three blackboards.The original one-hour academic report meeting has already passed half an hour, and everyone has not sensed the time. Why did half an hour pass in a blink of an eye?There is still half an hour left, can Zhuang Weiran solve the weak Goldbach conjecture?
In other words, has Zhuang Weiran really solved the weak Goldbach conjecture?This question came to everyone's mind, and they were looking forward to Zhuang Weiran's weak Goldbach's conjecture.
Zhuang Weiran's speed was getting faster and faster, and everyone felt dazzled.
Come to open the blackboard, Zhuang Weiran continued to write down the formula.
In 15 minutes, this academic report will be finished.Basically, everyone has already done a good job in the psychological construction of extending the academic report, and the weak Goldbach's conjecture cannot be written in an hour.Naturally, they didn't have any complaints. There are too many bosses at the scene, no matter what
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